5/(5-p)-p^2/(5-p)=2

Solution for 5/(5-p)-p^2/(5-p)=2 equation:

5/(5-p)-p^2/(5-p)=2

We move all terms to the left:

5/(5-p)-p^2/(5-p)-(2)=0


Domain of the equation: (5-p)!=0

We move all terms containing p to the left, all other terms to the right

-p!=-5

p!=-5/-1

p!=+5

p∈R


We add all the numbers together, and all the variables

-p^2/(-1p+5)+5/(-1p+5)-2=0

We multiply all the terms by the denominator


-p^2-2*(-1p+5)+5=0

We add all the numbers together, and all the variables

-1p^2-2*(-1p+5)+5=0

We multiply parentheses

-1p^2+2p-10+5=0

We add all the numbers together, and all the variables

-1p^2+2p-5=0

a = -1; b = 2; c = -5;
Δ = b2-4ac
Δ = 22-4·(-1)·(-5)
Δ = -16
Delta is less than zero, so there is no solution for the equation